Author: tlinnet
Date: Fri Aug 15 15:11:09 2014
New Revision: 25027
URL: http://svn.gna.org/viewcvs/relax?rev=25027&view=rev
Log:
Modification to the relax manual, regarding the Linear Constraints for the
exchange rate.
Modified:
trunk/docs/latex/dispersion.tex
Modified: trunk/docs/latex/dispersion.tex
URL:
http://svn.gna.org/viewcvs/relax/trunk/docs/latex/dispersion.tex?rev=25027&r1=25026&r2=25027&view=diff
==============================================================================
--- trunk/docs/latex/dispersion.tex (original)
+++ trunk/docs/latex/dispersion.tex Fri Aug 15 15:11:09 2014
@@ -1952,7 +1952,10 @@
\end{pmatrix},
\end{equation}
-and for the exchange rate and time parameters as
+Reasonable limits for the exchange rate can be found in \citet[p.
224]{PalmerKroenkeLoria01}.
+``In most cases of practical interest, CPMG experiments in proteins will
be applicable to chemical exchange processes with values of $kex < 1e^4$
\ldots''.
+``$\Ronerho$ experiments will be limited to values of $kex < 1e5$, or
approximately an order of magnitude faster than CPMG experiments.''
+The linear constraints for exchange rate is therefore set dependent on
experiment type, and is set to
\begin{equation}
\begin{pmatrix}
1 & 0 & 0 & 0 & 0 & 0 & 0 \\
@@ -1982,17 +1985,17 @@
\geqslant
\begin{pmatrix}
0 \\
- -2e^6 \\
+ -1e^4 / -1e^5 \\
0 \\
- -2e^6 \\
+ -1e^4 / -1e^5 \\
0 \\
- -2e^6 \\
+ -1e^4 / -1e^5 \\
0 \\
- -2e^6 \\
+ -1e^4 \\
0 \\
- -2e^6 \\
+ -1e^4 \\
0 \\
- -2e^6 \\
+ -1e^4 \\
0 \\
\end{pmatrix}.
\end{equation}
@@ -2017,12 +2020,12 @@
0 \leqslant \pB \leqslant \pA, \\
0 \leqslant \pC \leqslant \pA, \\
\pA \geqslant 0.85 \quad (\textrm{the skewed condition, } \pA \gg
\pB), \\
- 0 \leqslant \kex \leqslant 2e^6, \\
- 0 \leqslant \kexAB \leqslant 2e^6, \\
- 0 \leqslant \kexBC \leqslant 2e^6, \\
- 0 \leqslant \kA \leqslant 2e^6, \\
- 0 \leqslant \kB \leqslant 2e^6, \\
- 0 \leqslant \kAB \leqslant 2e^6, \\
+ 0 \leqslant \kex \leqslant 1e^4 / 1e^5, \\
+ 0 \leqslant \kexAB \leqslant 1e^4 / 1e^5, \\
+ 0 \leqslant \kexBC \leqslant 1e^4 / 1e^5, \\
+ 0 \leqslant \kA \leqslant 1e^4, \\
+ 0 \leqslant \kB \leqslant 1e^4, \\
+ 0 \leqslant \kAB \leqslant 1e^4, \\
\tex \geqslant 0.
\end{gather}
\end{subequations}
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