Author: tlinnet Date: Wed May 7 10:14:09 2014 New Revision: 23030 URL: http://svn.gna.org/viewcvs/relax?rev=23030&view=rev Log: Used LaTeX subequations instead, and using R2eff parameter is defined in the relax.tex Using the defined \Rtwoeff, \RtwozeroA, \RtwozeroB, \kAB, \kBA, \kex. sr #3154: (https://gna.org/support/?3154) Implementation of Baldwin (2014) B14 model - 2-site exact solution model for all time scales. This follows the tutorial for adding relaxation dispersion models at: http://wiki.nmr-relax.com/Tutorial_for_adding_relaxation_dispersion_models_to_relax#The_relax_manual Modified: trunk/docs/latex/dispersion.tex Modified: trunk/docs/latex/dispersion.tex URL: http://svn.gna.org/viewcvs/relax/trunk/docs/latex/dispersion.tex?rev=23030&r1=23029&r2=23030&view=diff ============================================================================== --- trunk/docs/latex/dispersion.tex (original) +++ trunk/docs/latex/dispersion.tex Wed May 7 10:14:09 2014 @@ -565,21 +565,26 @@ This is the model for 2-site exchange exact analytical derivation on all time scales (with the constraint that $\pA > \pB$), named after \citet{Baldwin2014}. It is selected by setting the model to `B14 full'. The equation is -\begin{eqnarray} - R_{2,\textrm{eff}} & = & \frac{R_2^A+R_2^B+k_{\textrm{EX}}}{2}-\frac{N_{\textrm{CYC}}}{T_{\textrm{rel}}}\cosh{}^{-1}(v_{1c}) \nonumber \\ - & - & \frac{1}{T_{\textrm{rel}}}\ln{\left( \frac{1+y}{2} + \frac{1-y}{2\sqrt{v_{1c}^2-1}}(v_2 + 2k_{\textrm{AB}}p_D )\right)} \nonumber \\ - & = & R_{2,\textrm{eff}}^{\textrm{CR72}} - \frac{1}{T_{\textrm{rel}}}\ln{\left( \frac{1+y}{2} + \frac{1-y}{2\sqrt{v_{1c}^2-1}}(v_2 + 2k_{\textrm{AB}}p_D )\right)} , -\end{eqnarray} +\begin{subequations} +\begin{align} + \Rtwoeff & = \frac{\RtwozeroA + \RtwozeroB + \kex }{2}-\frac{ N_{\textrm{CYC}} }{ T_{\textrm{rel}} } \cosh{}^{-1}(v_{1c}) \\ + & - \frac{1}{T_{\textrm{rel}}}\ln{\left( \frac{1+y}{2} + \frac{1-y}{2\sqrt{v_{1c}^2-1}}(v_2 + 2 \kAB p_D )\right)} \\ + & = \Rtwoeff^{\textrm{CR72}} - \frac{1}{T_{\textrm{rel}}}\ln{\left( \frac{1+y}{2} + \frac{1-y}{2\sqrt{v_{1c}^2-1}}(v_2 + 2\kAB p_D )\right)} , +\end{align} +\end{subequations} + where -\begin{eqnarray} - v_{1c} & = & F_0\cosh{\left(\tau_{\textrm{CP}}E_0\right)}-F_2\cosh{\left(\tau_{\textrm{CP}}E_2\right)} \nonumber \\ - v_{1s} & = & F_0\sinh{\left(\tau_{\textrm{CP}}E_0\right)}-F_2\sinh{\left(\tau_{\textrm{CP}}E_2\right)} \nonumber \\ - v_{2}N & = & v_{1s}\left(O_B-O_A\right)+4O_B F_1^a \sinh{\left(\tau_{\textrm{CP}}E_1\right)} \nonumber \\ - p_D N & = & v_{1s} + \left(F_1^a+F_1^b\right)\sinh{\left(\tau_{\textrm{CP}}E_1\right)} \nonumber \\ - v_3 & = & \left( v_2^2 + 4 k_{\textrm{BA}} k_{\textrm{AB}} p_D^2 \right)^{1/2} \nonumber \\ - y & = & \left( \frac{v_{1c}-v_3}{v_{1c}+v_3} \right)^{N_{\textrm{CYC}}} -\end{eqnarray} +\begin{subequations} +\begin{align} + v_{1c} & = F_0\cosh{\left(\tau_{\textrm{CP}}E_0\right)}-F_2\cosh{\left(\tau_{\textrm{CP}}E_2\right)} \\ + v_{1s} & = F_0\sinh{\left(\tau_{\textrm{CP}}E_0\right)}-F_2\sinh{\left(\tau_{\textrm{CP}}E_2\right)} \\ + v_{2}N & = v_{1s}\left(O_B-O_A\right)+4O_B F_1^a \sinh{\left(\tau_{\textrm{CP}}E_1\right)} \nonumber \\ + p_D N & = v_{1s} + \left(F_1^a+F_1^b\right)\sinh{\left(\tau_{\textrm{CP}}E_1\right)} \\ + v_3 & = \left( v_2^2 + 4 \kBA \kAB p_D^2 \right)^{1/2} \\ + y & = \left( \frac{v_{1c}-v_3}{v_{1c}+v_3} \right)^{N_{\textrm{CYC}}} +\end{align} +\end{subequations} The advantage of this code will be that you will always get the right answer provided you got 2-site exchange, in-phase magnetisation and on-resonance pulses.