Author: bugman Date: Fri May 9 09:42:44 2014 New Revision: 23118 URL: http://svn.gna.org/viewcvs/relax?rev=23118&view=rev Log: Small edits to the text of the B14 dispersion model section of the manual. Modified: trunk/docs/latex/dispersion.tex Modified: trunk/docs/latex/dispersion.tex URL: http://svn.gna.org/viewcvs/relax/trunk/docs/latex/dispersion.tex?rev=23118&r1=23117&r2=23118&view=diff ============================================================================== --- trunk/docs/latex/dispersion.tex (original) +++ trunk/docs/latex/dispersion.tex Fri May 9 09:42:44 2014 @@ -576,7 +576,7 @@ where Appendix 1 in \citet{Baldwin2014} list the recipe for exact calculation of $\Rtwoeff$. Note that the following definitions are different to those in the original publication, but match both the reference implementation and the relax implementation. The definitions are functionally equivalent. -Establish the complex free precession eigenfrequency with +First establish the complex free precession eigenfrequency with \begin{subequations} \begin{align} \Delta \Rtwozero & = \RtwozeroA - \RtwozeroB , \\ @@ -588,13 +588,12 @@ \end{align} \end{subequations} -The ground state ensemble evolution frequency $f_{00}$ expressed in separated real and imaginary components, in terms -of definitions $\zeta , \Psi , h_3 , h_4$ is +The ground state ensemble evolution frequency $f_{00}$ expressed in separated real and imaginary components, in terms of definitions $\zeta$, $\Psi$, and $h_4$ is \begin{equation} f_{00} = \frac{1}{2}\left(\RtwozeroA + \RtwozeroB + \kex\right) + \frac{\imath}{2}\left(\dw - h_4\right) . \end{equation} -Define substitutions for `stay' and `swap' factors are +Define substitutions for `stay' and `swap' factors as \begin{subequations} \begin{align} N & = h_3 + \imath h_4 , \\ @@ -606,7 +605,7 @@ \end{align} \end{subequations} -Weighting factors for frequencies ($E_{0-2}$) emerging from a single CPMG block, ($F_{0-2}$), are +The weighting factors for frequencies $E_{0-2}$ emerging from a single CPMG block, $F_{0-2}$, are \begin{subequations} \begin{align} E_0 & = 2 \taucpmg \cdot h_3 , \\ @@ -615,8 +614,8 @@ \end{align} \end{subequations} -Here $\taucpmg = 1 / 4\nucpmg $. -Final result, with identities to assist efficient matrix exponentiation optimised for numerical calculation is +Here $\taucpmg = 1 / 4\nucpmg$. +The final result, with identities to assist efficient matrix exponentiation optimised for numerical calculation is \begin{subequations} \begin{align} \nu_{1c} & = F_0 \cosh(E_0) - F_2 \cos(E_2) , \\