Author: tlinnet Date: Fri Aug 15 15:11:09 2014 New Revision: 25027 URL: http://svn.gna.org/viewcvs/relax?rev=25027&view=rev Log: Modification to the relax manual, regarding the Linear Constraints for the exchange rate. Modified: trunk/docs/latex/dispersion.tex Modified: trunk/docs/latex/dispersion.tex URL: http://svn.gna.org/viewcvs/relax/trunk/docs/latex/dispersion.tex?rev=25027&r1=25026&r2=25027&view=diff ============================================================================== --- trunk/docs/latex/dispersion.tex (original) +++ trunk/docs/latex/dispersion.tex Fri Aug 15 15:11:09 2014 @@ -1952,7 +1952,10 @@ \end{pmatrix}, \end{equation} -and for the exchange rate and time parameters as +Reasonable limits for the exchange rate can be found in \citet[p. 224]{PalmerKroenkeLoria01}. +``In most cases of practical interest, CPMG experiments in proteins will be applicable to chemical exchange processes with values of $kex < 1e^4$ \ldots''. +``$\Ronerho$ experiments will be limited to values of $kex < 1e5$, or approximately an order of magnitude faster than CPMG experiments.'' +The linear constraints for exchange rate is therefore set dependent on experiment type, and is set to \begin{equation} \begin{pmatrix} 1 & 0 & 0 & 0 & 0 & 0 & 0 \\ @@ -1982,17 +1985,17 @@ \geqslant \begin{pmatrix} 0 \\ - -2e^6 \\ + -1e^4 / -1e^5 \\ 0 \\ - -2e^6 \\ + -1e^4 / -1e^5 \\ 0 \\ - -2e^6 \\ + -1e^4 / -1e^5 \\ 0 \\ - -2e^6 \\ + -1e^4 \\ 0 \\ - -2e^6 \\ + -1e^4 \\ 0 \\ - -2e^6 \\ + -1e^4 \\ 0 \\ \end{pmatrix}. \end{equation} @@ -2017,12 +2020,12 @@ 0 \leqslant \pB \leqslant \pA, \\ 0 \leqslant \pC \leqslant \pA, \\ \pA \geqslant 0.85 \quad (\textrm{the skewed condition, } \pA \gg \pB), \\ - 0 \leqslant \kex \leqslant 2e^6, \\ - 0 \leqslant \kexAB \leqslant 2e^6, \\ - 0 \leqslant \kexBC \leqslant 2e^6, \\ - 0 \leqslant \kA \leqslant 2e^6, \\ - 0 \leqslant \kB \leqslant 2e^6, \\ - 0 \leqslant \kAB \leqslant 2e^6, \\ + 0 \leqslant \kex \leqslant 1e^4 / 1e^5, \\ + 0 \leqslant \kexAB \leqslant 1e^4 / 1e^5, \\ + 0 \leqslant \kexBC \leqslant 1e^4 / 1e^5, \\ + 0 \leqslant \kA \leqslant 1e^4, \\ + 0 \leqslant \kB \leqslant 1e^4, \\ + 0 \leqslant \kAB \leqslant 1e^4, \\ \tex \geqslant 0. \end{gather} \end{subequations}