Re: value.set function create the err version of the parameter. -- October 23, 2013 - 18:50

Hi,

Was this unexpected?  The error flag allows the parameter error rather
than value to be set, so that is the correct behaviour.  Were you
trying to do something different?

Regards,

Edward




On 23 October 2013 18:26, Troels Emtekær Linnet <tlinnet@xxxxxxxxxxxxx> wrote:
> Hi Edward.
>
> This test script:
>
> ----------
> pipe.create(pipe_name='test', bundle='test', pipe_type='relax_disp')
>
> spin.create(spin_name='N', spin_num=1, res_name='V', res_num=2,
> mol_name=None)
> spin.create(spin_name='N', spin_num=2, res_name='F', res_num=3,
> mol_name=None)
> spin.create(spin_name='N', spin_num=3, res_name='G', res_num=4,
> mol_name=None)
> spin.create(spin_name='N', spin_num=4, res_name='R', res_num=5,
> mol_name=None)
> spin.create(spin_name='N', spin_num=5, res_name='C', res_num=6,
> mol_name=None)
>
> relax_disp.cluster('model_cluster', ':2@N')
> relax_disp.cluster('model_cluster', ':3@N')
>
> value.set(val = 8.5, param='r2', spin_id=':2@N', error=True)
> value.set(val = 500, param='kex', spin_id=':3@N', error=True)
>
> state.save('test', force=True)
> ----------
>
> If I load the saved state, and inspect the spins in the spin viewer, I see
> that the
> parameters are set for:
> r2_err = 8.5
> kex_err = 500
>
> Is this the expected behavior?
>
> best
> Troels
>
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